A. Double Cola Solution

#include <iostream>

#include <string>

using namespace std;

int main()

{

    int n;

    cin >> n;

    int r = 1;

    while (r * 5 < n)

    {

        n -= r * 5;

        r *= 2;

    }

    string names[] = {"Sheldon", "Leonard", "Penny", "Rajesh", "Howard"};

    cout << names[(n - 1) / r] << endl;

    return 0;

}